Room 43 Math 09
Wednesday, October 13, 2010
Monday, June 21, 2010
Exam Review Study Guide
Define
perpendicular- Describes line that intersect at right angle
Parallel- Line that never meet
Intersection- Line that Cross at any angle
perpendicular bisector-A line that divides a line segment in a half
Angle bisector- of a triangle is a line segment that bisects one of the vertex angle of a triangle.
acute angle- An acute angle is one which is less than 90°
Define
perpendicular- Describes line that intersect at right angle
Parallel- Line that never meet
Intersection- Line that Cross at any angle
perpendicular bisector-A line that divides a line segment in a half
Angle bisector- of a triangle is a line segment that bisects one of the vertex angle of a triangle.
acute angle- An acute angle is one which is less than 90°
Obtuse angle- An angle whose measure is greater than 90° and less than 180°
Label
Parallel
Intersection
Angle bisector Perpendicular bisector
Label
Parallel
Intersection
Angle bisector Perpendicular bisector
Friday, June 18, 2010
Measures of Central Tendancy
Mean- a measure of central tendancy
You can find the mean by the sum (adding) of a set of values divided by the number of values in the set.
eg. 4,5,8,9,9
=4+5+8+9+9 / 5
=35 / 5
=7 <- that is the mean or average
mean-7
median-7
mode-7
b)300,250,400,300,250
-250,250,300,300,400
mean-300
median-300
mode-250 and 300
You can find the mean by the sum (adding) of a set of values divided by the number of values in the set.
eg. 4,5,8,9,9
=4+5+8+9+9 / 5
=35 / 5
=7 <- that is the mean or average
mean-7
median-7
mode-7
b)300,250,400,300,250
-250,250,300,300,400
mean-300
median-300
mode-250 and 300
PG. 431-432 # 2-16
Measure of Central Tendency
- is a value that represents the centre of a set of data
- can be mean, median, mode
Median - the middle number in a set of data after the data has been arranged or ordered
eg. 2, 5, 6, 8, 9 median is 6
eg. 1, 3, 6, 8, 9, 10 median is 7
*add the two middle values together then divide by two : 6 + 8 = 14 14 divided by 2 = 7
*to find the median of data sets with an even number of values (eg. 2, 3, 4, 5, 6, 7) you have to use the above steps (add together , divide sum by 2, or in other words, find the mean/average)
Mode - the most frequently occuring number in a set of data
eg. 3, 5, 7, 7, 9 mode: 7
eg. 2, 2, 4, 6, 6, 8, 11 mode: 2 and 6
eg. 1, 2, 3, 4 mode: none
eg. 1, 2, 2, 2, 3, 3, 4, 4 mode: 2
eg. 2, 3, 2, 3, 4, 2, 4, 3, 4
2, 2, 2, 3, 3, 3, 4, 4, 4 mode: none
Mean - a measure of central tendency
- the sum (adding) of a set of values divided by the number of values in a set
eg. 4, 5, 8, 9, 9
= 4 + 5 + 8 + 9 + 9 divided by 5 = 35 divided by 5
= 7 - this is the mean
Mean - A. K. A. - average
Try these, find Mean, Median, Mode.
A) 7, 8, 6, 9, 9, 5, 7, 7, 8 ,4
4, 5, 6, 7, 7, 7, 8, 8, 9, 9 median: 7 mode: 7 mean: 7
B) 300, 250, 400, 300, 250
250, 250, 300, 300, 400 median: 300 mode: 250 and 300 mean: 300
Here are some websites to give you some extra help if you're still stuck.
http://www.mun.ca/educ/ed4361/virtual_academy/campus_a/losinskim/mean,median,mode.html
- can be mean, median, mode
Median - the middle number in a set of data after the data has been arranged or ordered
eg. 2, 5, 6, 8, 9 median is 6
eg. 1, 3, 6, 8, 9, 10 median is 7
*add the two middle values together then divide by two : 6 + 8 = 14 14 divided by 2 = 7
*to find the median of data sets with an even number of values (eg. 2, 3, 4, 5, 6, 7) you have to use the above steps (add together , divide sum by 2, or in other words, find the mean/average)
Mode - the most frequently occuring number in a set of data
eg. 3, 5, 7, 7, 9 mode: 7
eg. 2, 2, 4, 6, 6, 8, 11 mode: 2 and 6
eg. 1, 2, 3, 4 mode: none
eg. 1, 2, 2, 2, 3, 3, 4, 4 mode: 2
eg. 2, 3, 2, 3, 4, 2, 4, 3, 4
2, 2, 2, 3, 3, 3, 4, 4, 4 mode: none
Mean - a measure of central tendency
- the sum (adding) of a set of values divided by the number of values in a set
eg. 4, 5, 8, 9, 9
= 4 + 5 + 8 + 9 + 9 divided by 5 = 35 divided by 5
= 7 - this is the mean
Mean - A. K. A. - average
Try these, find Mean, Median, Mode.
A) 7, 8, 6, 9, 9, 5, 7, 7, 8 ,4
4, 5, 6, 7, 7, 7, 8, 8, 9, 9 median: 7 mode: 7 mean: 7
B) 300, 250, 400, 300, 250
250, 250, 300, 300, 400 median: 300 mode: 250 and 300 mean: 300
Here are some websites to give you some extra help if you're still stuck.
http://www.mun.ca/educ/ed4361/virtual_academy/campus_a/losinskim/mean,median,mode.html
http://simon.cs.vt.edu/sosci/Site/MMM/mmm.html
Here is a link to a video that is catchy and helps to remember the mean, median, and mode.
http://www.youtube.com/watch?v=uydzT_WiRz4
Sorry it's a link, I couldn't get it to upload.
Props to Julibella :). I saw the video on her post and it gave me the idea to use it.
Measures of Central Tendancy
How to find the mean is by the sum(adding) of a set of values divided by the number of values in the set.
eg. 1+2+3=6/3 eg. 4,5,8,9,9
3 sets of values
=4+5+8+9+9/5
=35/5
=7<- this is the mean. a.k.a average
Try this mean, median, mode
A) 7,8,6,9,9,5,7,7,8,4
mean-7
median-7
mode-7
B) 300,250,300,300,400 pg.431-433 #2-16
http://www.youtube.com/watch?v=QH2obAPwfqk
-Here is a video about mean, median and mode. I hope it helps:)
eg. 1+2+3=6/3 eg. 4,5,8,9,9
3 sets of values
=4+5+8+9+9/5
=35/5
=7<- this is the mean. a.k.a average
Try this mean, median, mode
A) 7,8,6,9,9,5,7,7,8,4
mean-7
median-7
mode-7
B) 300,250,300,300,400 pg.431-433 #2-16
http://www.youtube.com/watch?v=QH2obAPwfqk
-Here is a video about mean, median and mode. I hope it helps:)
exam review
Subscribe to:
Posts (Atom)